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x=4x^2-20x+24
We move all terms to the left:
x-(4x^2-20x+24)=0
We get rid of parentheses
-4x^2+x+20x-24=0
We add all the numbers together, and all the variables
-4x^2+21x-24=0
a = -4; b = 21; c = -24;
Δ = b2-4ac
Δ = 212-4·(-4)·(-24)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{57}}{2*-4}=\frac{-21-\sqrt{57}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{57}}{2*-4}=\frac{-21+\sqrt{57}}{-8} $
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